1-3x(2x+1)(x^2-4)=

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Solution for 1-3x(2x+1)(x^2-4)= equation:


Simplifying
1 + -3x(2x + 1)(x2 + -4) = 0

Reorder the terms:
1 + -3x(1 + 2x)(x2 + -4) = 0

Reorder the terms:
1 + -3x(1 + 2x)(-4 + x2) = 0

Multiply (1 + 2x) * (-4 + x2)
1 + -3x(1(-4 + x2) + 2x * (-4 + x2)) = 0
1 + -3x((-4 * 1 + x2 * 1) + 2x * (-4 + x2)) = 0
1 + -3x((-4 + 1x2) + 2x * (-4 + x2)) = 0
1 + -3x(-4 + 1x2 + (-4 * 2x + x2 * 2x)) = 0
1 + -3x(-4 + 1x2 + (-8x + 2x3)) = 0

Reorder the terms:
1 + -3x(-4 + -8x + 1x2 + 2x3) = 0
1 + -3x(-4 + -8x + 1x2 + 2x3) = 0
1 + (-4 * -3x + -8x * -3x + 1x2 * -3x + 2x3 * -3x) = 0
1 + (12x + 24x2 + -3x3 + -6x4) = 0

Solving
1 + 12x + 24x2 + -3x3 + -6x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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